Asked by Joe
                Verify the following identity
2 tan x/1+tan^2 x = sin 2x
            
        2 tan x/1+tan^2 x = sin 2x
Answers
                    Answered by
            Reiny
            
    One of the variations of sin^x + cos^x = 1 is
1 + tan^2x = sec^2x
so
LS = [2(sinx/cosx)]/sec^2x
= (2sinx/cosx)(1/cos^2x)
= 2sinxcosx
= sin 2x
= RS
    
1 + tan^2x = sec^2x
so
LS = [2(sinx/cosx)]/sec^2x
= (2sinx/cosx)(1/cos^2x)
= 2sinxcosx
= sin 2x
= RS
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