Asked by Peter
verify the identity:
1-cos^2x/1-sinx= -sinx
1-cos^2x/1-sinx= -sinx
Answers
Answered by
Damon
assume you mean (this took some serious detective work - please be careful with parentheses)
1- (cos^2x)/(1-sinx)= -sinx
cos^2x = 1 - sin^2 x
so we have
1 - (1-sin x)(1+sin x)/(1-sin x) = -sin x
1 - (1+sin x) = -sin x
1 - 1 - sin x = -sin x
-sin x = -sin x
1- (cos^2x)/(1-sinx)= -sinx
cos^2x = 1 - sin^2 x
so we have
1 - (1-sin x)(1+sin x)/(1-sin x) = -sin x
1 - (1+sin x) = -sin x
1 - 1 - sin x = -sin x
-sin x = -sin x
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