Question
verify the identity:
1-cos^2x/1-sinx= -sinx
1-cos^2x/1-sinx= -sinx
Answers
assume you mean (this took some serious detective work - please be careful with parentheses)
1- (cos^2x)/(1-sinx)= -sinx
cos^2x = 1 - sin^2 x
so we have
1 - (1-sin x)(1+sin x)/(1-sin x) = -sin x
1 - (1+sin x) = -sin x
1 - 1 - sin x = -sin x
-sin x = -sin x
1- (cos^2x)/(1-sinx)= -sinx
cos^2x = 1 - sin^2 x
so we have
1 - (1-sin x)(1+sin x)/(1-sin x) = -sin x
1 - (1+sin x) = -sin x
1 - 1 - sin x = -sin x
-sin x = -sin x
Related Questions
verify the identity sin(4u)=2sin(2u)cos(2u)
verify the identity:
tan^2x(1+cot^2x)=1/1-sin^2x
Verify the Id:
tanx + cotx/ tanx-cotx = (1/s...
verify the identity:
sin(x+y)-sin(x-y)=2cosx siny
verify the following identity used in calculus: cos(x+h)-cos(x)/h=cos(x)[cos(h)-1/h]-sin(x)[sin(h)/h...
verify the identity:
(sin^3x-cos^3x)/(sinx-cosx)=1+sinxcosx
Verify the following identity: sin(x)*cos(x)*(cot(x)+tan(x))=1
show work
PLEASE VERIFY THE IDENTITY
cot(theta-pi/2) = -tan theta
Verify the Identity:
sin(x+π)/cos(x+3π/2) =tan^2x-sec^2x
I've done:
sinxcosπ+cosxsinπ
/
cosx...
Verify the identity cot{0-pi/2=-tan 0
Verify the following identity. Show all your work. Don't skip any steps.
Do not change the right s...