Asked by AwesomeGuy
Solve the equation for all values of x.
2sin(2x)-√3=0, on the interval [0,2π).
2sin(2x)-√3=0, on the interval [0,2π).
Answers
Answered by
Steve
sin2x = √3/2
so, 2x = π/3, 2π/3, 7π/3, 8π/3
x = π/6, π/3, 7π/6, 4π/3
so, 2x = π/3, 2π/3, 7π/3, 8π/3
x = π/6, π/3, 7π/6, 4π/3
There are no AI answers yet. The ability to request AI answers is coming soon!