Asked by AwesomeGuy
Solve the equation for all values of x.
-2cos²x-sin x+1=0, on the interval [0,2π).
-2cos²x-sin x+1=0, on the interval [0,2π).
Answers
Answered by
Steve
-(2cosx-1)(cosx+1) = 0
so, where is cosx = 1/2 or -1?
so, where is cosx = 1/2 or -1?
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.