Asked by AwesomeGuy
Solve the equation for all values of x.
-2cos²x-sin x+1=0, on the interval [0,2π).
-2cos²x-sin x+1=0, on the interval [0,2π).
Answers
Answered by
Steve
-(2cosx-1)(cosx+1) = 0
so, where is cosx = 1/2 or -1?
so, where is cosx = 1/2 or -1?
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