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CoCl2CO+Cl2 Keq=7.6*10^-4 M CoCl2 is
can you explain me how to do this question. any help would be much appreciated.
1) If 0.025 mol of COCl2(g) is placed in a one
1 answer
asked by
hrithik
561 views
Phosgene is a potent chemical warfare agent that is now outlawed by international agreement. It decomposes by the reaction
1 answer
asked by
Emem
1,492 views
The equation for synthesis of the poisonous gas COCl2 is
CO(g) + Cl2(g)COCl2 If 43.2 kJ of energy is evolved when 39.5 g of COCl2
2 answers
asked by
Melissa
2,484 views
Carbonyl chloride, COCl2, is prepared by the reaction: CO(g) + Cl2(g) → COCl2(g)
The suggested reaction mechanism is: Cl2(g)
5 answers
96 views
the initial pressure of phosgene gas (COCl2), was 1.31 atm. it was heated, and at equilibrium the pressure of CO was found to be
2 answers
asked by
Blair
706 views
1.62 g of CoCl2 x (xH20) were heated. After heating only .88g of CoCl2 remained. What was the formula of the original hydrate?
3 answers
asked by
Courtney
2,483 views
Starting with o.3700 mol CO (g) and 5.400*10^-2 COCl2 (g), in a 3 liter flask at 668 K, how many moles of Cl2 will be present?
CO
1 answer
asked by
anonymous
513 views
At 298K, Go = -67.4 kJ for the reaction
CO + Cl2 --> CoCl2 Calculate the change in Gibbs free energy (in kJ) at the same
4 answers
asked by
Mike
771 views
A 1.00 L flask containing the equilibrium mixture CO +Cl2 <-> COCl2 was found to contain 0.400 mol of COCl2, 0.100 mol of CO,
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asked by
Divya
1,552 views
Starting with 0.3500mol Co(g) and 0.05500mol COCL2(g) in a 3.050 L flask at 668K, how many moles of Cl2 are present at
4 answers
asked by
K
2,575 views