Asked by Ifi
Differentiate ln (1+ cos x)...
My ans is (-sin x)/ (1+cos x), but at wolfram is
-tan (x/2). I think they simplify it but how did they do it? Sorry for my little knowlegde....
My ans is (-sin x)/ (1+cos x), but at wolfram is
-tan (x/2). I think they simplify it but how did they do it? Sorry for my little knowlegde....
Answers
Answered by
Steve
look up your half-angle formulas. This is a standard form.
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