Asked by Zac
Differentiate: y = 3/(1-6x^4)
Answers
Answered by
Reiny
I would write it as
y = 3(1 - 6x^4)^-1 , and use the chain rule
dy/dx = -3(1 - 6x^4)^-2 (-24x^3
= 72x^3/(1 - 6x^4)^2
y = 3(1 - 6x^4)^-1 , and use the chain rule
dy/dx = -3(1 - 6x^4)^-2 (-24x^3
= 72x^3/(1 - 6x^4)^2
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