Asked by Wes
Differentiate: y = (x^2 + 8x +3)^3
Answers
Answered by
Steve
if y = u^n,
dy/dx = n u^(n-1) du/dx, so
y' = 3(x^2 + 8x +3)^2 * (2x+8)
dy/dx = n u^(n-1) du/dx, so
y' = 3(x^2 + 8x +3)^2 * (2x+8)
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