Asked by Brett
Differentiate
f(x)=(x^(3)-8)^(2/3)
Please Show Work
f(x)=(x^(3)-8)^(2/3)
Please Show Work
Answers
Answered by
Steve
Just use the good old chain rule.
f = (x<sup>3</sup>-8)<sup>2/3</sup>
f' = 2/3 * (x<sup>3</sup>-8)<sup>-1/3</sup> * 3x<sup>2</sup>
f' = 2x<sup>2</sup>/(x<sup>3</sup>-8)<sup>1/3</sup>
f = (x<sup>3</sup>-8)<sup>2/3</sup>
f' = 2/3 * (x<sup>3</sup>-8)<sup>-1/3</sup> * 3x<sup>2</sup>
f' = 2x<sup>2</sup>/(x<sup>3</sup>-8)<sup>1/3</sup>
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