Asked by paula
differentiate y = 2^3x^2
read as two to the 3x squared power
read as two to the 3x squared power
Answers
Answered by
bobpursley
y=a^kx
y'= k*a^(kx)*ln(a)
y'= k*a^(kx)*ln(a)
Answered by
Steve
y = 2^(3x^2)
y' = ln2 * 6x * 2^(3x^2)
it helps to go at it like this
y = 2^(3x^2)
ln y = 3x^2 ln2
1/y y' = 6x ln2
y' = ln2 6x 2^(3x^2)
y' = ln2 * 6x * 2^(3x^2)
it helps to go at it like this
y = 2^(3x^2)
ln y = 3x^2 ln2
1/y y' = 6x ln2
y' = ln2 6x 2^(3x^2)
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