Asked by Anonymous
Differentiate.
f(x)=(cos x)/x
I got to here:
(-x sin x - cos x)/x^2
Find the equation of the tangent line to
f(x)=sec x - 2 cos x at (pi/3, 1).
Is the slope 3 times sqrt of 3?
Equation is y=3 times sqrt of 3x - pi times sqrt of 3 +1??
f(x)=(cos x)/x
I got to here:
(-x sin x - cos x)/x^2
Find the equation of the tangent line to
f(x)=sec x - 2 cos x at (pi/3, 1).
Is the slope 3 times sqrt of 3?
Equation is y=3 times sqrt of 3x - pi times sqrt of 3 +1??
Answers
Answered by
Steve
(f'(π/3) = (-π/3 * √3/2 - 1/2)/(π/3)^2
= -(9π-3√3)/(2π^2)
If we call that slope m, then the tangent line is
y-1 = m(x-π/3)
= -(9π-3√3)/(2π^2)
If we call that slope m, then the tangent line is
y-1 = m(x-π/3)
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.