Asked by Joey
Differentiate.
g(x) = 5e^x√x
g(x) = 5e^x√x
Answers
Answered by
Reiny
product rule:
g ' (x) = (5e^x)(1/2)x^(-1/2) + x^(1/2) (5e^x)
clean it up any way you know how
g ' (x) = (5e^x)(1/2)x^(-1/2) + x^(1/2) (5e^x)
clean it up any way you know how
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