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Ifi
Questions (15)
1. If -1/infinity = infinity or -infinity ?
2. If lim x->infinity^- = infinity & lim x->inifinity^+ = -infinity, then lim
0 answers
578 views
Given table,
X (1+x)^(1/x) -0.5. 4 -0.1 2.8680 -0.01 2.7320 -0.001 2.7196 0.001 2.7169 0.01 2.7048 0.1 2.5937 0 5 2.25 From the
0 answers
533 views
If f(x)=3x^2-5x, find the f'(2) & use it to find an equation of tangent line to the parabola
y=3x^2-5x at the point (2,2). My ans
1 answer
1,298 views
Differentiate ln (1+ cos x)...
My ans is (-sin x)/ (1+cos x), but at wolfram is -tan (x/2). I think they simplify it but how did
1 answer
436 views
Differentiate y=4^(3x^2)..
i need to know the calculation step..thanks for the help....
1 answer
319 views
How to differentiate f(x)=e^(xlnx)?
I get f'(x)=e^(xlnx) (1+lnx) while at wolfram is x^x(ln x+x)...sorry for my miscalculation /
1 answer
566 views
How to differentiate e^e^x?
Ans at wolfram is e^(x+e^x). I need the calculation method.
1 answer
410 views
Differentiate f(x)= (8-2x)^3(x^2+1)^5.
My ans is 2(8-2x)^2(x^2+1)^4(-3x^2-10x+37). Plz recheck my simplify ans. -my simplify ans
3 answers
499 views
Let f(x) be the parabola -x^2+16x-16. find the point (x,y) on f such that tangent line to f at (x,y) passes through the origin.
M
1 answer
480 views
find the intervals of increase and decrease of f(x)=3/(x*2+11) -1 ?
My f'(x) is-6x/(x^2+1)^2, after that i didn't know how to
1 answer
387 views
Calculate dy/dx, (x^3)(y^7) + 16xy^6=0
My ans is (y(-16-3x^2y))/ x(96+7x^2y) but at wolfram is y^6(3x^2y+16). Btw i use product
2 answers
385 views
If f(1)=-2 & f'(x)_< 1.8 for 1_< x_< 8, what is the largest possible value of f(8)?
Can someone help me on this question and plz
2 answers
385 views
Let f(t)=2t^4-2x^2-9. at what x does f have a local or absolute minimum or maximum?
I think the question is wrong bcus it is
1 answer
447 views
dx/dy cos x sin y + x^5 = 11
i got dx/dy= (-cos x cos y)/ (-sin x sin y +5x^4) But the wolfram got (1- cos x cos y)/(5x^4-sin y
3 answers
541 views
How to d/dx
y= (9+((x-9)/6)^1/5)^1/2 ? Hope u can give me the way how to calculate it. ^^ I got 1/60 ((x-9)/6) ^ (-9/10), i think
4 answers
621 views
Answers (5)
I still don't get it how do u simplify from = (8-2x)^2 (x^2+1)^4 (26x^2 - 80x + 6) to = -8(4-x)^2 (x^2+1)^4 (13x^2 - 40x + 3) ... ? What can i conclude from it is (4-x)^2 &(13x^2 - 40x + 3) is divided by 2 . Then (x^2+1)^4 is not simplified by any no.
Thanks guy
Thanks steve
At reiny .... Thanks
thanks for the calculation but i think there is a mistake at implicit diff. y^2= 9 + ((x-9)/6)^(1/5) 2y dy/dx = 1/5 ((x-9)/6)^(-4/5)) (1/6) dy/dx = 1/60y ((x-9)/6)^(-4/5) ..... Sorryif im wrong Btw why at wolfram the answer is 1/( 60y(-9+y^2)^4). Why is