Asked by Ifi

How to differentiate f(x)=e^(xlnx)?
I get f'(x)=e^(xlnx) (1+lnx) while at wolfram is x^x(ln x+x)...sorry for my miscalculation / typo error...

13 years ago

Answered by Steve

Your answer is correct, since e^(x lnx) = (e^(lnx))^x = x^x

13 years ago

There are no AI answers yet. The ability to request AI answers is coming soon!

Submit Your Answer

We prioritize human answers over AI answers.

If you are human, and you can answer this question, please submit your answer.