Asked by Joshua

A gun fires a shell at an angle of elevation of 30 degrees with a velocity of 2*10^3m/s. What is the horizontal and vertical component of the velocity? What is the range of the shell? how high will the ball rise
Answered by Henry
Vo = 2000m/s @ 30o.
Xo = 2000*cos30.
Yo = 2000*sin30 = 1000 m/s.

Range = Vo^2*sin(2A)/g.
Vo = 2000 m/s.
2A = 60o.
g = 9.8m/s^2.

hmax = (Y^2-Yo^2)/2g.
hmax = (0-10^6)/19.6 = 51,020 m.
Answered by igho destiny
51,020m
Answered by shalom
My answer for the range is 346.4
Answered by Jessica
the answer is not explanable
Answered by mustapha
horizontal component
Answered by Akinsipe favour
Correct and good
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