Question
A cannon fires a 0.598 kg shell with initial velocity 10 m/s in the direction 46◦ above the horizontal.
The shell’s trajectory curves downward be- cause of gravity, so at the time t = 0.53 s the shell is below the straight line by some verti- cal distance ∆h. Your task is to calculate the distance ∆h in the absence of air resistance.
On what does ∆h depend (besides g)?
The shell’s trajectory curves downward be- cause of gravity, so at the time t = 0.53 s the shell is below the straight line by some verti- cal distance ∆h. Your task is to calculate the distance ∆h in the absence of air resistance.
On what does ∆h depend (besides g)?
Answers
Problem entirely vertical assuming your straight line is horizontal
Vi = 10 sin 46
v = Vi - g t
delta h = Vi t - (1/2) g t^2
Vi = 10 sin 46
v = Vi - g t
delta h = Vi t - (1/2) g t^2
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