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a cannon fires a shell with a speed of 84m/s.when the cannon is inclined at 45 degree,the horizontal distance covered is observed as 630 m.what is the percentage decrease in the horizontal distance observed due to air resistance?
11 years ago

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Henry
Vo = 84m/s[45o].

Dx = Vo^2*sin(2A)/g=84^2*sin90/9.8=720 m
with zero wind.

(720-630)/720 * 100% = 12.5% Decrease.


11 years ago

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