Asked by pranav prabhat
a cannon fires a shell with a speed of 84m/s.when the cannon is inclined at 45 degree,the horizontal distance covered is observed as 630 m.what is the percentage decrease in the horizontal distance observed due to air resistance?
Answers
Answered by
Henry
Vo = 84m/s[45o].
Dx = Vo^2*sin(2A)/g=84^2*sin90/9.8=720 m
with zero wind.
(720-630)/720 * 100% = 12.5% Decrease.
Dx = Vo^2*sin(2A)/g=84^2*sin90/9.8=720 m
with zero wind.
(720-630)/720 * 100% = 12.5% Decrease.
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