Answers by visitors named: Sean

I am supposed to do an essay on compartmentalization of cell respriation but i don't know what it means. my essay is as follows: Compartmentalization is important in carrying out cell respiration. Describe the use of compartmentalization in carrying out cell respiration. I just don't understand what they want me to write about.

(1) seven suits can be made (2) 29/85 yards of fabric remains

Help? Please?

Thanks. The next question I have is pretty similar. f(x) =cos(arcsin(2x)) Find f'(x)

passive voice (helping verb + infinitive....i.e. are overshadowed) tends to make writing weaker. if you can, try to change it to just the verb (rearranging the sentence may help). also, "the well-being of humans are overshadowed" isn't gramatically correct. it should be well beings are overshadowed or well-being of humans is overshadowed. when in doubt, it helps to cross out the prepositional phrase (of humans) because the well being is the subject and must agree in number with the verb. hope that helps a little bit! good job.

The radius is Half of the Diameter. So you would do 8/2 = 4 r=4

Thank you. That made it so much simpler.

There's my problem. I just can't factor the bottom.

Oh. Okay thanks. Thank you so much. If it's not to much... How would I integrate (4dt)/(sqrt(15-2t-t^2)) That thing has me stumped.

Reiny. You misunderstood. And I didn't word it right. I meant where does (Cx + D)/Something Pop up?

Wow. I'm making this topic last a while. I think- and this is just out loud- that you would do (Cx + D) Over the X^2 + 2? Am I getting that right? OR You have Cx + D over something if the SOMETHING has a term of X to a power greater than one?

Out of curiosity, where did the 'i' come from, and what technique did you use? Also, how did you write sin(3x) In terms of sin(x)?

Sorry. I lied. Misread the question. What is the indefinite integral of arccot(4x) ?

Thank you so much.

I've reached the last step of (7/5) ln((x+4)/(x+9) But how do I substitute the variable 't' back in?

Its actually supposed to be (cos(x/8))^3. With what Anonymous answered, I see he left out the x/8, instead only using x. Would you, Drwls, mind using x/8?

I can follow everything except when you change the (4 x pi)/3 to pi/6, and change pi/6 into 1/2. Could you clear that up for me?

Oh. Thank you, Damon, and Drwls. That really helped me out.

I don't quite get how you did the first one. Mainly the cos(1/2 x)

I got the first one, thanks for that. But on the second one, are you saying that x=(1/19)*(19x-7)+(7/19)? If so, would I just multiply the entire thing out, or what?

Thank you so much. You cleared that up really well. Thank you.

L'hopital is If the limit as x goes to (thing) of f(x)/g(x) is equal to an indeterminate form, lim as x goes to (thing) of f(x)/g(x) is equal to lim as x goes to (thing) of f'(x)/g'(x). Damon's answer confuses me.

Thanks, that cleared it up for me!

I messed up. I meant (x^2+1)^12

Haha, I definitely notice the amount of reading we are required to do. Since I wasn't there for the first two days of school, I have to make it up by reading 40 pages!

Wow, thanks for the help! Your effort is useful.

Thanks so much Iblis. Makes perfect sense!

Answer is e^2. lim (n -> infinity) of [(n+3)(n+1)]^n = lim (n -> infinity) of [1 + 2/(n+1)]^n e = lim (x -> infinity) of [1 + 1/x]^x e^2 = lim (x -> infinity) of [1 + 2/x + 1/x^2]^x

wow, I'm very impressed! Thanks so much Iblis!

You prove that the sequences converges to 2, but you don't necessarily prove that it will never exceed 2... Thanks for the great help though

You are absolutely correct. Thanks so much for the help on this! I'd love to pay you guys back for this service :)

subtract 1/3 from both sides 4/x = 2 - 1/3 = 5/3 multiply both sides by 3x/5 12/5 = x

1,2,3 are correct. It looks like you skipped an equal sign in the second equation in 4.

52/3, 52/3, 52/3 Product is 5,207.7037

That looks like a separable first-order differential equation rather than calc 2, but here goes: (separate both variables) P^-2 dP = k dt (integrate both sides) -1/P = kt + C P = -1 / (kt + C) Po = -1 / C C = -1 / Po P = -1 / (kt + -1/Po)

1/2 = 1 divided by 2 = 0.5 (times 100 to convert to %) = 50% 2/3 = 2 divided by 3 = 0.66666 (times 100 to convert to %) = 66.67% does that make sense?

a stop codon

There are 64 possible codon permutations since there are three nucleotides of 4 four possible values (4^3 = 64). That includes duplicates (codons that code for the same amino acid) and unused codons as well. There are fewer effective codon permutations.

I'd like to help, but I'm not sure what you mean by "doing radical expressions"...

Thanks Reiny! I couldn't factor that polynomial. Once there, the rest follows the book example Each term in the sequence: 1/(9k^2 + 3k - 2) = 1/((3k+2)(3k-1)) = 1/3*(1/(3k-1) - 1/(3k+2)) When you take a sum of those terms, it's a telescoping series where the -1/(3k+2) cancels the next +1/(3k-1) term. The sum of a partial series from terms 1 to n = 1/3*(1/2 - 1/(3n + 2)). Limit to infinity = 1/6

You are right Reiny. I got a little sloppy there and missed that.

Noble gas atoms rarely react with other chemicals and form compounds. When they do, the resulting compounds are usually unstable and do not last. Some larger noble gases (specifically Krypton and Xenon) do form certain stable compounds.

a) 88. Worst case: draw 29 of two colors before drawing 30 of the third color. b) 210. Worst case: draw all 100 of two colors, and then draw ten of the third color.

Fourth root is the same as to the 1/4th power, just like square root is the same as to the 1/2th power. Answer is: 16x^2 * y * z^4

So, you are assuming a true population with a normal distribution of 0.4; 0.023) A) Convert 0.45 to a Z score: (0.45 - 0.40) / 0.023 = +2.17 Look up on a z-table chart. Greater than +2.17 yields .0150 = 1.5% B) <= 0.35 has the exact opposite Z score: (0.35 - 0.40) / 0.023 = -2.17 Less than -2.17 yields .0150 = 1.5% (same answer as A)

Forgot C. That's probably obvious after you have A + B: C) 100% - 1.5% - 1.5% = 97%

Thanks so much Reiny! That's the right answer. I've been struggling with it for a few hours. Here's a slightly different route to the same answer: Sn = Π (1 to n) of (1 - 1/(k + 1)^2) = Π (1 to n) of (k^2 + 2k)/(k + 1)^2 Since Π of X * Y = Π X * Π Y and Π (1 to n) of k = n! and Π (1 to n) of (k + a) = (n + a)!/a! Π (1 to n) of (k^2 + 2k)/(k + 1)^2 = (Π k) * (Π k + 2) * (Π 1/(k + 1)) * (Π 1/(k + 1)) = n! * (n + 2)!/2 * 1/(n + 1)! * 1/(n + 1)! = 1/2 * (n + 2) / (n + 1)

That's e^Sn... Not Sn...

Ah, thanks! Makes perfect sense

Don't know why the options didn't show. they are NH3 F- H2O PF5 BrF3

Thanks for the headsup. Yeh I have drawn the Lewis structures. How do I know which ions can accept electrons? Does that mean it has a unpaired electron?

That works. Thanks so much!

Ah, thanks so much. My mind is working slowly today :)

Nevermind. I can now understand this at an intuitive level and a more formal proof isn't necessary.

Thanks so much! I can't read your symbols, but I can make out what you are doing and it results in the right answer.

Thanks! You guys are awesome. I would tip for this service if I could. The book's question was to get the first four terms of sin^2(x). Makes perfect sense.

The question was in the book. It was talking about Las Colonias "America's Third world"

Thank you for helping me

No I’m not surprised that poverty exists in the United States because some people have very low income.

I know the fundamental formulas and their derivations really well. This problem demands a more complicated application that I'm struggling with...

that looks correct

Maybe the book is wrong? Thanks for giving it a shot

OK, the book is definitely wrong. I emailed the author. At least I'm understanding the material correctly. Thanks!

BTW, author of book confirmed correction and will fix in next printing.

Makes sense. Thanks Count!

When k is an integer sin(x) = (sin x + 2k*pi) set k=2 and... sin(-27pi/6) = sin(-27pi/6 + 2*2*pi) = sin(-27pi/6 + 24pi/6) = sin(-pi/2) = -1

The 28 and 37 counts are overlapping. People who speak both languages are double counted... numEnglishSpeakers + numSpanishSpeakers - numBothSpeakers + numSpeakNeither = 50 28 + 37 - both + 5 = 50 both = 20

Hey, Your ANSWER is corrupt, cause it doesnt really explain anything! Try to make it more clear. SY

it's due in two days, lol SY

Thanks so much for the response. I ordered the books. I bought two books in case one isn't a good fit. My main concern was that there is some other theoretical prerequisites that I'm not aware of that I should be studying before diving into Fourier analysis. Thanks!

the answer i provided was from the back of the book.

how did you get 3(route)/112 ?

yeah I did mine wrong. Hopefully I'll get partial credit on the test.

This sounds like a trick question. If the standard deviation of the answer from the general population is 16, then the variance is σ2, which is 256.

What are the similarities and differences?

So what does the derivative of the f(x) have to do with the graphs? Or is the derivative part of the main question: define the function f with the formula? And what would be the similarities and differences of the graphs? And if you increase c then does the slope change?

What kind of similarities and differences is it asking for?

So then there are no similarities? And the differences are the shapes and the distinct roots, max and min?

Okay thank you very much

Is this the correct answers? 1-1 and 5 2-soaked, croaked 3-named, blaze 4-soaked, croaked 5-first,filly 6-which,filly

Thank you so much

Forget it... Inside the cavity of a charged metal object (such as a sphere or cylinder), there is no net field. The net field exists only on the outside. That explains it.

It has something to do with functions. We are working on this in a 9th grade ACC Math class

Computer program says the answer is x/(a*(a^2 + x^2)^(1/2)) which is slightly different from your answer. Thanks so much for the help on this one. I was really stuck.

I did x = a tan u dx = a (sec u)^2 du int of a/(a^2 + x^2)^3/2 dx = int of (a sec u)^2/(a^2 + (a tan u)^2)^3/2 du = int of (a sec u)^2/(a sec u)^3 du = int of (cos u)/a du = (sin u)/a + K since u = atan (x/a) = x/(a*(a^2 + x^2)^(1/2)) + K Thanks again...

A Squared + B squared = C squared

(5.0x10^2)/5.0

i still don't understand how to write this equation

i don't understand the d1/d2=a1/a2.

so you set it up like the following? d1*.30=(62-d1).17 It has been several years since I had algebra and it should be common sense but how do I get the d1 by itself?

Pthagorean theorem: square root of (6*6+8*8) is 10.

b. sunk cost

(x,8) and (6,-16) can you give me the answer that's all I need thanks

thanks man!

Where a and b are integers 3 + 13*a = x 3 + 14*b = x Subtract one line from the other: 14*b = 13*a smallest integers that satisfy that are 14, 13. so: 3 + 13*14 = x 3 + 14*13 = x x = 185

thank you!! :D

60/100 = 3/5

U.S.

You are awesome Iblis. That limit was the tricky part. I followed your proof and it makes perfect sense. Thanks

I meant that summation was the tricky part (not limit). thanks again.