Question
A trench mortar fires a shell at an angle of 30° with the horizontal and with a speed of 400 m/s. Find its range and the maximum height it attains. (a)Range (b) Height
Answers
Anonymous
if you don't have the formulas handy, you can find them and their derivations in the wikipedia article on Trajectory.
Anonymous
vertical speed = 200 = Vi
m g h = (1/2) m Vi^2
solve for h = 200^2 / (2g) = max height
find time to top
v = Vi - g t
0 at top so
t = 200 / g at top
time in air = 2 t = 400/g
horizontal speed = 400 cos30 = u
range = u * 400/g
m g h = (1/2) m Vi^2
solve for h = 200^2 / (2g) = max height
find time to top
v = Vi - g t
0 at top so
t = 200 / g at top
time in air = 2 t = 400/g
horizontal speed = 400 cos30 = u
range = u * 400/g