Asked by AFOLABI IDRIS.
A gun fires a shell at an angle of elevation of 30* with a velocity of 2000ms-1.(A)what is the range of the shell.
Answers
Answered by
bobpursley
time in air:
hf=hi+2000sin30*t-4.9t^2
hf=hi=0
t=2000sin30/4.9
range:
d=2000*cos30*timeinair
hf=hi+2000sin30*t-4.9t^2
hf=hi=0
t=2000sin30/4.9
range:
d=2000*cos30*timeinair
Answered by
Steve
the fine article in wikipedia on "trajectory" explains this and more. The formula for the range is
R = v^2/g sin(2θ)
R = v^2/g sin(2θ)
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