Vo = 500m/s[30o]
Xo = 500*cos30 = 433 m/s.
Yo = 500*sin30 = 250 m/s.
Tr = -Yo/g = -250/-9.8 = 25.5 s. = Rise
time.
Tf = Tr = 25.5 s. = Fall time.
Tr+Tf = 25.5 + 25.5 = 51 s. = Time in air.
Dx = Xo*(Tr+Tf) = 433*51 = 22,083 m. =
Distance travelled by the shell.
D = Dx + Dt = 22,083 + 4m/s*51s. = 22,287 m. = Distance from mortar to tank.
A mortar fires a projectile at an angle of of 30 degrees above the horizontal with a velocity of 500 m/s. A soldier spots a tank to be travelling in the direction of the mortar at a constant the rate of 4 m/s. How far should the tank be from the mortar before the mortar is fired in order to hit the tank?
2 answers
17.35
1 answer