Asked by Strom
A mortar fires a projectile at an angle of of 30 degrees above the horizontal with a velocity of 500 m/s. A soldier spots a tank to be travelling in the direction of the mortar at a constant the rate of 4 m/s. How far should the tank be from the mortar before the mortar is fired in order to hit the tank?
Answers
Answered by
Henry
Vo = 500m/s[30o]
Xo = 500*cos30 = 433 m/s.
Yo = 500*sin30 = 250 m/s.
Tr = -Yo/g = -250/-9.8 = 25.5 s. = Rise
time.
Tf = Tr = 25.5 s. = Fall time.
Tr+Tf = 25.5 + 25.5 = 51 s. = Time in air.
Dx = Xo*(Tr+Tf) = 433*51 = 22,083 m. =
Distance travelled by the shell.
D = Dx + Dt = 22,083 + 4m/s*51s. = 22,287 m. = Distance from mortar to tank.
Xo = 500*cos30 = 433 m/s.
Yo = 500*sin30 = 250 m/s.
Tr = -Yo/g = -250/-9.8 = 25.5 s. = Rise
time.
Tf = Tr = 25.5 s. = Fall time.
Tr+Tf = 25.5 + 25.5 = 51 s. = Time in air.
Dx = Xo*(Tr+Tf) = 433*51 = 22,083 m. =
Distance travelled by the shell.
D = Dx + Dt = 22,083 + 4m/s*51s. = 22,287 m. = Distance from mortar to tank.
Answered by
Anonymous
17.35
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.