Asked by toor
a toy cannon fires a projectile from ground level with a speed of 15.0 m/s, at an angle of 30.0 degrees above the horizontal.
a) calculate the horizontal range of projectile.
R=Vi^2/g * sin 2theta
= (150/9.8)*(sin(2*30.0)
= 19.88m
I know this part is right but i'm not sure what to do next?
b) calculate the maximum height for the trajectory.
c) calculate the components of the projectile's impact velocity.
a) calculate the horizontal range of projectile.
R=Vi^2/g * sin 2theta
= (150/9.8)*(sin(2*30.0)
= 19.88m
I know this part is right but i'm not sure what to do next?
b) calculate the maximum height for the trajectory.
c) calculate the components of the projectile's impact velocity.
Answers
Answered by
Elena
R=vₒ²•sin2α/g,
h= vₒ²•sin²α/2g,
t= 2vₒ•sinα/g
v(x) =v₀(x)= v₀•cos α
v(y) =-v₀(y) = - v₀•sin α
h= vₒ²•sin²α/2g,
t= 2vₒ•sinα/g
v(x) =v₀(x)= v₀•cos α
v(y) =-v₀(y) = - v₀•sin α
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