Question
A Mortar shell is fired with muzzle speed of 500ft/sec.Find the angle of elevation of mortar if the shell strikes a target located 1200ft away. What is the maximum height of the shell?
Answers
Henry
a. Range = Vo^2*sin(2A)/g
Range = 1200 Ft.
Vo = 500 Ft./s.
g = 32 Ft/s^2
Solve for A.
b. V^2 = Vo^2 + 2g*h
h = -Vo^2/2g
Vo = 500 Ft./s.
g = -32 Ft./s^2
Solve for h
Range = 1200 Ft.
Vo = 500 Ft./s.
g = 32 Ft/s^2
Solve for A.
b. V^2 = Vo^2 + 2g*h
h = -Vo^2/2g
Vo = 500 Ft./s.
g = -32 Ft./s^2
Solve for h