Asked by Trinity
An artillery shell is fired with an initial velocity of 450 m/s at an angle of 37° from the level ground. 1) how much time passes before the shell strikes the ground? 2) What horizontal distance does the shell travel before striking the ground?
Answers
Answered by
oobleck
v = 450 sin37° - 9.8t
v=0 at the top of the arc. So double that time for the full trip.
using the flight time from above, the horizontal speed is a constant
450 cos37°
and distance = speed * time, right?
v=0 at the top of the arc. So double that time for the full trip.
using the flight time from above, the horizontal speed is a constant
450 cos37°
and distance = speed * time, right?
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