Asked by Anonymous

An artillery shell is fired at an angle of 66.1 degrees above the horizontal ground with an initial speed of 1650 m/s. The acceleration of gravity is 9.8 m/s2 . Find the total time of flight of the shell,neglecting air resistance.
Answered by Scott
time up equals time down (still)

initial vertical velocity is __ 1650 * sin(66.1º)

flight time is __ 2 * 1650 * sin(66.1º) / 9.8
Answered by Anonymous
307.8610257 minutes
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