Asked by Anonymous
An artillery shell is fired from a cannon with an elevation of a = 30° and muzzle velocity of v = 300 m/s . Find the time of flight of the shell, and its range.
Answers
Answered by
oobleck
the height is
y = 300 sin30° - 4.9t^2 = 150t - 4.9t^2
so find when y=0
and the range is 150 cos30° * t
y = 300 sin30° - 4.9t^2 = 150t - 4.9t^2
so find when y=0
and the range is 150 cos30° * t
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