Asked by Anonymous
An artillery shell is fired at an angle of 45.3◦ above the horizontal ground with an initial speed of 1710 m/s.
The acceleration of gravity is 9.8 m/s2 .
Find the total time of flight of the shell,
neglecting air resistance.
Answer in units of min.
The acceleration of gravity is 9.8 m/s2 .
Find the total time of flight of the shell,
neglecting air resistance.
Answer in units of min.
Answers
Answered by
bobpursley
Look at the vertical...that is what time it is in the air.
Hf=Hi+vivert*time- 1/2 g time^2
solve for time
vivert=1710*sin45.3 m/s
Hf=Hi+vivert*time- 1/2 g time^2
solve for time
vivert=1710*sin45.3 m/s
Answered by
pedro
An artillery shell is fired at an angle of 67.1◦ above the horizontal ground with an initial speed of 1580 m/s.
The acceleration of gravity is 9.8 m/s2 .
Find the total time of flight of the shell, neglecting air resistance.
Answer in units of min.
The acceleration of gravity is 9.8 m/s2 .
Find the total time of flight of the shell, neglecting air resistance.
Answer in units of min.
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