Question
A person standing near the edge of a cliff 120 feet above a lake throws a rock upward with an initial speed of 40 feet per second. The height of the rock above the lake at the bottom of the cliff is a function of time and is described by the function H(t) = –16t2 + 40t + 120.
a) How many seconds will it take until the rock reaches its maximum height?
b) What is that height?
a) How many seconds will it take until the rock reaches its maximum height?
b) What is that height?
Answers
H(t) = -16t^2 + 40t + 120
Finding critical point...
H'(t) = -32t + 40 ...... Differentiation
0 = -32t + 40
32t = 40
t = 1.25 seconds
Thats you answer for (a). Use it to find the answer for (b).
Finding critical point...
H'(t) = -32t + 40 ...... Differentiation
0 = -32t + 40
32t = 40
t = 1.25 seconds
Thats you answer for (a). Use it to find the answer for (b).
Thats you...
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