Asked by Ashley
A person standing at the edge of a seaside cliff kicks a stone over the edge with a speed of vi = 14 m/s. The cliff is h = 39 m above the water's surface.
(a) How long does it take for the stone to fall to the water?
(b) With what speed does it strike the water?
(a) How long does it take for the stone to fall to the water?
(b) With what speed does it strike the water?
Answers
Answered by
Marth
(a)
d = Vi*t + (1/2)*a*t^2
Keep in mind that to use the equation to find time with respect to displacement in height, consider only the vertical component of the initial velocity. (You did not specify a direction for the initial velocity).
(b)
Having found the time from part (a), use a = (Vf - Vi)/t to find the velocity when it hits the water.
d = Vi*t + (1/2)*a*t^2
Keep in mind that to use the equation to find time with respect to displacement in height, consider only the vertical component of the initial velocity. (You did not specify a direction for the initial velocity).
(b)
Having found the time from part (a), use a = (Vf - Vi)/t to find the velocity when it hits the water.
Answered by
karl
a)2.910
b)11.089
b)11.089
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