Asked by steph
A person standing at the edge of a seaside cliff kicks a stone over the edge with a speed of vi = 11 m/s. The cliff is h = 47 m above the water's surface, as shown below.
Answers
Answered by
drwls
You gave the details but failed to ask the question.
If you want to know how far away from the (vertical) cliff the stone hits the water, multiply 11 m/s by the time T that it takes the stone to fall to the water's surface.
(g/2)T^2 = 47 m
T = sqrt (2*47/9.8)= 3.1 s
If you want to know how far away from the (vertical) cliff the stone hits the water, multiply 11 m/s by the time T that it takes the stone to fall to the water's surface.
(g/2)T^2 = 47 m
T = sqrt (2*47/9.8)= 3.1 s
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.