51 = 4.9 t^2
solve for t
d = 31 t
v = 9.81 t vertical and 31 horizontal
so speed = sqrt ( v^2+31^2)
a person standing at the edge of a seaside cliff kicks a stone horizontally over the edge with speed of 31 m/s cliff is 51 m above water. how far from base of cliff does stone land and what is speed of stone when it hits water
1 answer
1 answer