Question

a person standing at the edge of a seaside cliff kicks a stone horizontally over the edge with speed of 31 m/s cliff is 51 m above water. how far from base of cliff does stone land and what is speed of stone when it hits water
51 = 4.9 t^2
solve for t

d = 31 t

v = 9.81 t vertical and 31 horizontal
so speed = sqrt ( v^2+31^2)

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