A diver jumps from a diving board that is 32 feet above the water. The height of the diver is given by

h= -16(t-2)(t+1)
where the height h is measured in feet, and the time t is measured in seconds. When will the diver hit the water?

1 answer

solve
h = -16(t-2)(t+1) = 0

There two solution, t = -1 and t = +2 s.

In real situation with correct physics, the equation would be
h = 32 - 16t^2 = 16(2 - t^2)
= 16(t + sqrt2)(sqrt2 - t) and solutions would bedifferent.