Asked by Anonymous
A diver jumps from a diving board that is 32 feet above the water. The height of the diver is given by
h= -16(t-2)(t+1)
where the height h is measured in feet, and the time t is measured in seconds. When will the diver hit the water?
h= -16(t-2)(t+1)
where the height h is measured in feet, and the time t is measured in seconds. When will the diver hit the water?
Answers
Answered by
drwls
solve
h = -16(t-2)(t+1) = 0
There two solution, t = -1 and t = +2 s.
In real situation with correct physics, the equation would be
h = 32 - 16t^2 = 16(2 - t^2)
= 16(t + sqrt2)(sqrt2 - t) and solutions would bedifferent.
h = -16(t-2)(t+1) = 0
There two solution, t = -1 and t = +2 s.
In real situation with correct physics, the equation would be
h = 32 - 16t^2 = 16(2 - t^2)
= 16(t + sqrt2)(sqrt2 - t) and solutions would bedifferent.
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