A diver jumps off a 10m diving board with an initial upward velocity of 5.0 m/s. What is the diver's velocity after 1.5 seconds?

Answer 1

Initially, the diver is moving upwards
0 = Vo – gt,
t = Vo/g ≈ 5/10 = 0.5 s.
After 0.5 seconds of motion the diver is at the maximum height.
Then the downward motion begins.
After 1.5 - 0,5 = 1 second of motion the velocity of diver is
v = g•t = 10•1= 10 m/s.