A diver jumps off of a diving board. She leaves the board with a velocity of 3.70 m/sec in the upward direction. How far will she rise above the diving board before she reverses her motion and starts to fall downward?

asked by Tara

8 years ago

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1 answer

PE at top= KE at start
mgh=1/2 m v^2
solve for h.

answered by bobpursley

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Question

A diver jumps off of a diving board. She leaves the board with a velocity of 3.70 m/sec in the upward direction. How far will she rise above the diving board before she reverses her motion and starts to fall downward?

1 answer

PE at top= KE at start
mgh=1/2 m v^2
solve for h.

bobpursley · Answer

PE at top= KE at start mgh=1/2 m v^2 solve for h.