do horizontal and vertical problems separately
v = g t velocity down
h = 0 + Vo t + (1/2) g t^2 height
so
height = 4.9 (2.6)^2
height = 33.1 meters (high all right)
U = horizontal speed = constant
d = u t = 2.8 * 2.6 = 7.28 meters away
Phil jumps off a high-diving platform with a horizontal velocity if 2.8 m/s and lands in the water 2.6 seconds later.
a. How high is the platform
b. How far out from where he jumped does he land?
1 answer
1 answer