Janet jumps off a high-diving platform with a horizontal velocity of 3.5 m/s and lands in the water 1.7 s later. How high is the platform, and how far from the base of the platform does she land?

Answer 1

When finding how high the platform is the horizontal velocity isn't important.
S= 1/2at^2 where S is the displacement and a is the acceleration due to gravity (9.8)
so
S=(1/2) (9.8) 1.7^2
S=4.9*1.7^2
S=14.161 meters

When finding how far from the base Janet lands use the formula:
D=Ut where D= the distance from the platform, U= the horizontal velocity, and t= time
So:
D=Ut
D=3.5*(1.7)
D=5.95
Simple isn't it?

Answer 2

Janet jumps off a high diving platform with a horizontal velocity of 2.64 m/s and lands in the water 2.8 s later. How high is the platform? The acceleration of gravity is 9.8^2 m/s. Answer in units of m