Asked by Elizabeth
Janet jumps off a high diving platform with
a horizontal velocity of 2.37 m/s and lands in
the water 1.9 s later.
How high is the platform? The acceleration
of gravity is 9.8 m/s
2
.
Answer in units of m
a horizontal velocity of 2.37 m/s and lands in
the water 1.9 s later.
How high is the platform? The acceleration
of gravity is 9.8 m/s
2
.
Answer in units of m
Answers
Answered by
Steve
The horizontal velocity is unimportant. No one is asking how far away from the platform she lands.
So, all we want to know is how far one falls in 1.9s under gravity.
s = .5at^2 = 4.9*1.9^2 = 17.7m
That's a nice high platform!
So, all we want to know is how far one falls in 1.9s under gravity.
s = .5at^2 = 4.9*1.9^2 = 17.7m
That's a nice high platform!
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