Question
A pipe of length 10.0 m increases in length by 1.5 cm when its temperature is increased by 90°F. What is its coefficient of linear expansion?
Answers
drwls
alpha = (deltaL/L)/(deltaT)
= (0.015/10)/90 F
= 1.7*10^-5 F^-1
or 3.0*10^-5 degC^-1
= (0.015/10)/90 F
= 1.7*10^-5 F^-1
or 3.0*10^-5 degC^-1
JJ
Ok thank you
Jim
What is the correct answer