Question
An open pipe 0.40m in length is placed vertically in a cylindrical bucket having a bottom area of 0.10 m^2. Water is poured into the bucket until a sounding tuning fork of frequency 440 Hz, placed over the pipe, produces resonance. Find the mass of water in the bucket at this moment.
I've been totally stumped in this, all I got was a very brief overview of standing waves in open and closed air columns. Totally lost.
I've been totally stumped in this, all I got was a very brief overview of standing waves in open and closed air columns. Totally lost.
Answers
bobpursley
The closed pipe is 1/4 lambda long (closed at the bottom due to water).
so the height of the water is .4-1/4 lambda
volume water= area*heighwater
mass water=denstiy water*volume water
so the height of the water is .4-1/4 lambda
volume water= area*heighwater
mass water=denstiy water*volume water
Related Questions
In the figure below, S is a small loudspeaker driven by an audio oscillator with a frequency that is...
Water flows into a cylindrical tank through pipe 1 at a rate of 25 ft/s and leaves through pipe 2 at...
A bucket is 20cm in diameter at the open end 12cm in diameter at the bottom and 16cm deep.To what de...
A bucket is 20cm in diameter at the open 12cm in diameter at the bottom and 16cm deep.To what depth...