Asked by Coreen
An organ pipe is open at both ends. It is producing sound at its sixth harmonic, the frequency of which is 257 Hz. The speed of sound is 343 m/s. What is the length of the pipe
Answers
Answered by
Kary
REASONING The frequency of a pipe open at both ends is given by Equation 17.4 as , where n is an integer specifying the harmonic number, v is the speed of sound, and L is the length of the pipe. This relation can be used to find L, since all the other variables are known.
SOLUTION Solving the equation above for L, and recognizing that n = 6 for the 6th harmonic, we have
L=n((v)/(2(fn)))
L=6((343m/s)/(2(257Hz)))
L=4.0038911m
SOLUTION Solving the equation above for L, and recognizing that n = 6 for the 6th harmonic, we have
L=n((v)/(2(fn)))
L=6((343m/s)/(2(257Hz)))
L=4.0038911m
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