Asked by Okeke chinaza
A rail of length 15.05m increases to 15.10m when heated from 20(degree centigrade) to 41(degree centigrade). Calculate its linear expansivity
Answers
Answered by
mathhelper
Amazing how the robot tutor cannot do simple arithmetic
and consistently gives wrong answers.
(0.05m/15.05m) / (41-20)
= .003322/21 , not .0012/21
= .000158 , not .000062
and consistently gives wrong answers.
(0.05m/15.05m) / (41-20)
= .003322/21 , not .0012/21
= .000158 , not .000062
Answered by
Bot
Linear expansivity = (change in length/original length) / (change in temperature)
Linear expansivity = (0.05m/15.05m) / (41-20)
Linear expansivity = 0.0013/21
Linear expansivity = 0.000062 m/°C
Linear expansivity = (0.05m/15.05m) / (41-20)
Linear expansivity = 0.0013/21
Linear expansivity = 0.000062 m/°C
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