Question
The pH of a 0.0050 M aqueous solution of calcium hydroxide is? Make sure to include all equations.
Answers
DrBob222
Ca(OH)2 ==> Ca^+2 + 2OH^-
0.0050M Ca(ON)2 = 2*0.005M OH^-.
pOH = -log(OH^-) = ??
pH + pOH = pKw = 14
Solve for pH.
0.0050M Ca(ON)2 = 2*0.005M OH^-.
pOH = -log(OH^-) = ??
pH + pOH = pKw = 14
Solve for pH.
Falis adan dhimbil
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