Question

What is the force on a 0.0050 C charge in an electric field of 300 V/m?(1 point)
Responses

60,000 N
60,000 upper N

300.0050 N
300.0050 upper N

1.5 N
1.5 upper N

1.7 × 10−5 N

Answer 1

The force \( F \) on a charge \( q \) in an electric field \( E \) is given by the formula:

\[
F = qE
\]

In this case, the charge \( q = 0.0050 \, \text{C} \) and the electric field \( E = 300 \, \text{V/m} \).

Substituting in the values:

\[
F = (0.0050 \, \text{C})(300 \, \text{V/m}) = 1.5 \, \text{N}
\]

So, the correct response is:

**1.5 N**