Question

50.00 mL of 0.567 M aqueous NaOH solution and 75.00 mL of 0.348 M aqueous HCl solution were combined in a simple (coffee cup) calorimeter. Determine how many moles of NaOH will actually react in this calorimeter.
This is another problem that is not a calorimeter problem. It is a simple stoichiometry problem.
NaOH + HCl ==> NaCl + H2O
mols NaOH = mols x L = 0.567 M x 0.0500 L = 0.0283
mols HCl = 0.348 x 0.075 = 0.0261
Since this is a 1:1 reaction (1 mol NaOH to 1 mol HCl), then 0.0261 mols NaOH will react. mols NaOH unreacted will be 0.0283 - 0.0261 = ?

A 50 ml of 10 Molar aqueous sodium hydroxide solutions from solid NaOH.

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