Asked by derrick
What is the pH of an aqueous solution of a weakly acidic drug that is 40% dissociated and has a pKa =4.7?
Answers
Answered by
DrBob222
Call the weak acid HA.
............HA ==> H^+ + A^-
initial.....X......0.......0
change...-0.4x...0.4x....0.4x
equil...0.6x....0.4x.....0.4x
Ka (H^+)(A^-)/(HA)
Substitute the equil line into the Ka exparession and solve for x, then (H^+) + 0.4x. Convert to pH = -log(H^+)
............HA ==> H^+ + A^-
initial.....X......0.......0
change...-0.4x...0.4x....0.4x
equil...0.6x....0.4x.....0.4x
Ka (H^+)(A^-)/(HA)
Substitute the equil line into the Ka exparession and solve for x, then (H^+) + 0.4x. Convert to pH = -log(H^+)
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.