Asked by bruh
If 240 mL of 0.583 M aqueous H2SO4 and 89.1 g of solid CaCO3 are reacted stoichiometrically according to the balanced equation, how many grams of solid CaCO3 remain? Round your answer to 3 significant figures.
H2SO4(aq) + CaCO3(s) → CO2(g) + CaSO4(s) + H2O(l)
thank u drbob222
H2SO4(aq) + CaCO3(s) → CO2(g) + CaSO4(s) + H2O(l)
thank u drbob222
Answers
Answered by
oobleck
240mL * 0.583M = 0.140 moles of H2SO4
That will use up 0.140 moles of CaCO3
Convert that to grams and subtract from 89.1
That will use up 0.140 moles of CaCO3
Convert that to grams and subtract from 89.1
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