Asked by Anonymous
If 18.4 mL of a 1.37 M aqueous KCl solution was placed in a 150-mL volumetric flask and water was added to dilute to the mark, after mixing, how many moles of KCl would be in the flask?
(with correct number of sig figs)
(with correct number of sig figs)
Answers
Answered by
DrBob222
mols = M x L = 1.37 x 0.0184 = ? You can have 3 significant figures in the answer.
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