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If 18.4 mL of a 1.37 M aqueous KCl solution was placed in a 150-mL volumetric flask and water was added to dilute to the mark, after mixing, how many moles of KCl would be in the flask?
(with correct number of sig figs)
4 years ago

Answers

DrBob222
mols = M x L = 1.37 x 0.0184 = ? You can have 3 significant figures in the answer.
4 years ago

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