Asked by Anonymous

If 18.4 mL of a 1.37 M aqueous KCl solution was placed in a 150-mL volumetric flask and water was added to dilute to the mark, after mixing, how many moles of KCl would be in the flask?
(with correct number of sig figs)

Answers

Answered by DrBob222
mols = M x L = 1.37 x 0.0184 = ? You can have 3 significant figures in the answer.
There are no AI answers yet. The ability to request AI answers is coming soon!

Related Questions