Question

What is the force on a 0.0050 C charge in an electric field of 300 V/m?
answers:
60, 000 N

1.5N

1.7 x10-5N

300.0050 N

Answer 1

To find the force on a charge in an electric field, you can use the formula:

\[
F = qE
\]

where:
- \( F \) is the force,
- \( q \) is the charge, and
- \( E \) is the electric field strength.

Given:
- \( q = 0.0050 \, \text{C} \)
- \( E = 300 \, \text{V/m} \)

Now, substitute the values into the formula:

\[
F = 0.0050 \, \text{C} \times 300 \, \text{V/m}
\]

\[
F = 1.5 \, \text{N}
\]

So the force on the charge is **1.5 N**.

The correct answer from your options is:

**1.5 N**.