How many milliliters of 0.0050 N KOH are required to neutralize 19 mL of 0.0050 N H2SO4?

Question

How many milliliters of 0.0050 N KOH are required to neutralize 19 mL of 0.0050 N HCl?

Answer 1

For #2, mL x M = mL x M and that works because HCl and NaOH react 1:1.

For the first one,
moles H2SO4 = M x L.
Convert moles H2SO4 to moles KOH using the coefficients in the balanced equation.
Then M KOH = moles KOH/L of solution.