Asked by Lucy

How many milliliters of NH3 (at STP) are needed to react with 45.0 mL of NO2 (at STP) according to the equation:
8NO2 (g) + 6NH3 )g) yield 7N2O (g) + 9 H2O.

How to set this up?????

Thanks.
Answered by Lucy
The answer that I got was 33.8---is this correct.
Answered by DrBob222
Yes. I obtained 33.750 which rounds to 33.8 mL to three significant figures.
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